y1=√2sinπ/4=1,z1=5.
设点B的直角坐标为(x2,y2,z2),
则x2=√6sinπ/3cosπ/6=√6×√3/2×√3/2=(3√6)/4,
y2=√6sinπ/3sinπ/6=√6×√3/2×1/2=(3√2)/4,
z2=√6cosπ/3=√6×1/2=√6/2.
所以点P的直角坐标为(1,1,5),点B的直角坐标为
((3√6)/4,(3√2)/4,√6/2).