sin A=,sin B=,sin C=,
已知等式可化为a2-c2=ab,
即a2+b2-c2=ab.
由余弦定理,得cos C===,
∴C=.
∴S△ABC=absin C=×2Rsin A·2Rsin B·sin
=R2sin Asin B.
∵R=1,B=π-(A+C)=π-,
∴S△ABC=sin A·sin
=sin A·sin
=sin A
=sin2A+sin Acos A
=+sin 2A
=+
=+sin.
∴当sin=1,即A=时,Smax=.