解得x≠-3且x≠5.
(3)要使z为纯虚数,则x应满足
解得x=3或x=-2.
(4)要使z=-2-15i,则x应满足
解得x=0.
(5)要使z=0,则x应满足
解得x无解.
10.解:∵m2-(m2-3m)i<(m2-4m+3)i+10,
∴解得
故有m=3,
即实数m的值为3.