=,∴sin α-cos α=.∴sin α=,cos α=.
8.已知tan α+=,α∈,,求cos 2α和sin2α+的值.
【解析】由tan α+=,得+=,
则=,sin 2α=.
∵α∈,,∴2α∈,π,cos 2α=-=-.
sin2α+=sin 2αcos +cos 2αsin =×-×=.